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EUR/RC51/InfDoc/1 k l j 1 < < ?. E H X e c J A t @ x b g E H X e b J f B Y j E H X e b J v c F E H X e b J q X e b J Disney V f B Y j v Z X 킢 L N ^ g C X g g C v ~ b. Solution (a) If f(x;y;z)=x2 y2 z2 then a normal of the surface x2 y2 z2 =9at(2;2;1) is given by the gradient rf(x;y;z)j (2;2;1) =(2xi2yj2zk)jfx=2;y=2;z=1g=4i4j2k Actually we will take the normal to be n =2i2jkThe extra factor 2 is not needed Thus the equation of the tangent plane to.

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