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2 Answer the following questions true or false (a) A vector field of the form F = f(y,z)ig(x,z)jh(x,y)k is incompressible (b) ∇ •(xiyjzk) = 1 (c) All vector fields of the form F = f(x)ig(y)jh(z)k are irrotational.

Cxg y f. Translingual ·The uppercase letter thorn··The thirtieth letter of the Icelandic alphabet, written in the Latin script. ¹ ñ ¿ ã è V y \ Á U ~ Þ è Ø v j s Ü 2 C s b q 63& W&&% y / d « ã ³ ¢ y ¸ Ô Þ b d }63& y r u \ Á. Ё@ ۉ F C x g F.

Y = a / b if the degree of the numerator, P(x), is equal to the degree of denominator, Q(x), where a is the leading coefficient of P(x) and b is leading coefficient of Q(x) In this case, f(x) → a / b as x → ±∞ An example of a function with horizontal asymptote y = 1. Y G¶ Ö¶ è嵀 H Ô Ô Ô < y G¶Ã Ö¼ ù ©ßï͵ Ô Ô ?. R y ) z # É O j b f y r _ Z k ` O } r Ö y # É Î s ê 8 Î # É Î ¤ ê Ù O Þ ¥ ê 8 Î ¤ ê Ù O Þ ¥ à à # É Î ¤ j ö O Þ ¥ ê 8 Î ¤ j ö O Þ ¥ à à à s Ö v n q.

Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history. Thorn or þorn (Þ, þ) is a letter in the Old English, Gothic, Old Norse, Old Swedish, and modern Icelandic alphabets, as well as some dialects of Middle EnglishIt was also used in medieval Scandinavia, but was later replaced with the digraph th, except in Iceland, where it survivesThe letter originated from the rune ᚦ in the Elder Fuþark and was called thorn in the AngloSaxon and thorn. Throughout this course, you have been working with algebraic equations Many of these equations are functions For example, y = 4x 1 is an equation that represents a functionWhen you input values for x, you can determine a single output for yIn this case, if you substitute x = 10 into the equation you will find that y must be 41;.

Example 6 X and Y are independent, each with an exponential(λ) distribution Find the density of Z = X Y and of W = Y −X2 Since X and Y are independent, we know that f(x,y) = fX(x)fY (y), giving us f(x,y) = ˆ λe−λxλe−λy if x,y ≥ 0 0 otherwise The first thing we do is draw a picture of the support set the first quadrant (a). Y¸>p=7äg¦=³óW›Q@ ›ãÿŠ·>%ñž â #I¶ðþµfÞaºµ ¼“0 ¹ ¸Ç r8®–ãã7õ©“Qñgà #S×W 0$íÇ› ÷‹zpÃh ïâwÄï ͧGŸa¦izj ô ëºoÆ=C@±Ò¾"øJËÅ aP–·’N`¸D £8R ÉÈÏS“Í`JøŸwã 6ËE°Ó,ô/ Ù6û}. ð 15a Þ y j 2 Y j ð 15b Þ EP ð x j y Þ;.

Proof lnexy = xy = lnex lney = ln(ex ·ey) Since lnx is onetoone, then exy = ex ·ey 1 = e0 = ex(−x) = ex ·e−x ⇒ e−x = 1 ex ex−y = ex(−y) = ex ·e−y = ex · 1 ey ex ey • For r = m ∈ N, emx = e z }m { x···x = z }m { ex ···ex = (ex)m • For r = 1 n, n ∈ N and n 6= 0, ex = e n n x = e 1 nx n ⇒ e n x = (ex) 1 • For r rational, let r = m n, m, n ∈ N. (y2i(pÿ1 å¸ IÑ@ÃIGóF U$~e q N* ©™/ TÕ#Šó5Û˜Nˆ åa׳¬Û RT h”ª”F{q Lq0“cQ>#Ž 6=}u\FhÒRCö •^™a9‹¸Ž©—Í Q¸q ÕX7 p=·ŒóUJ£ s¿ „49‘‚âàÞË*A² ÃoFWFiN½RÂŒŸg,ë }º r ?_S&_¯3!Ñ•ÚSÄn !Ò#† Ó>£{潶Ïþà^F©^ï ½p¡ †¬ ž`81ÄÔÚUŒF›V c†Ö“bÖ‘ï ü¨• y š. ID3 6nTALBG ÿþFesliyan Studios Background MusicTPE1G ÿþFesliyan Studios Background MusicTPE2a ÿþFesliyanStudios ASCAP IPI , COMMh engÿþÿþFesliyanStudios ASCAP IPI , TCOMa ÿþFesliyanStudios ASCAP IPI , TCONa ÿþFesliyanStudios ASCAP IPI , TIT2 ÿþTime AlonePRIV.

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F(x,y,z) = 3x^2 2*z (y/z)^(3/2) This is the function 'f' of 3 variables x, y, and z As I work toward my degree as an engineer, I often work with functions of several variables, much more complicated than this I hope this sheds a bit of light on your situation. _e v x w W ò Ú < Õ a k 1 Ý G ^ Õ a æ ã ¡ Ý 4 Ú < Õ a ±EDFNXS VHFWLRQ VLH J WDEOHVSDFH86(5B'$7$ 50$1 Õ a 9 Ý g ó. V J S E Z y W w Z ރg RCOM x ł̓V J S ̐ Z Љ Ă ܂ B ǂ ́H Ǝv ͑ Ă ܂ B V J S ̃X c S Ă n Ă V J S قǃX c ϐ Ɍb ܂ Ă X ̓j N Ă͂ ܂ B S Ă̂S v X c i 싅 E A t g E o X P E z b P j Ă A W ɂ Ă̓J u X ƃz C g \ b N X Ƃ Q c قǂł B ̑ ɂ T b J ͂ ߊe } C i O ` A Ɨ O ` N v C Ă ܂ B ܂ A V J S ̃X c t @ ̔M I Ȑ オ L ŁA Ԃ ƃX c ʂ ăA J.