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Design and development The Fokker CX was originally designed for the Royal Dutch East Indies Army, in order to replace the Fokker CVLike all Fokker aircraft of that time, it was of mixed construction, with wooden wing structures and a welded steel tube frame covered with aluminium plates at the front of the aircraft and with fabric at the rear. 10 Assuming that Q is positive definite, we solve Qx˜ = −(c − AT u), ie, x˜ = −Q−1(c − AT u)and L∗ (u)=L(˜x, u)=− 1 2 (c − AT u)T Q−1(c − AT u)u T bThe dual problem (D) is 1 (D) max L ∗(u)=max− 2 (c − AT u)T Q−1(c − AT u)u T bu≥0 u≥0 55 Remarks on Problems with Different Formats of Constraints Suppose that our problem has some inequality and. ò$ L ò ò$ s < Í 5 Ü íA ?.

) n c x n( b c ?. W c k g a g l x c g. U t uu x =0, u(x,0)= h(x) (51) The characteristic equations are dx dt = z, dy dt =1, dz dt =0, and Γ may be parametrized by (s,0,h(s)) x = h(s)ts, y = t, z = h(s) u(x,y)=h(x−uy) (52) The characteristic projection in the xtplane1 passing through the point (s,0) is the line x = h(s)ts along which u has the constant value u = h(s) Two.

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D v i l ?. @ _ X A _ X A _ X!!. (a) For any constant k and any number c, lim x→c k = k (b) For any number c, lim x→c x = c THEOREM 1 Let f D → R and let c be an accumulation point of D Then lim x→c f(x)=L if and only if for every sequence {sn} in D such that sn → c, sn 6=c for all n, f(sn) → L Proof Suppose that lim x→c f(x)=LLet {sn} be a sequence in D which converges toc, sn 6=c for all nLet >0.

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