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M q Z s b c k y i j h ^ _ f h g k l j b j m _ l h l h \ g h k l d d h e e _ ^ ` m b i j h n _ k k b h g Z e v g h c 6 ^ _ y l _ e v g h k l b 4 8 ^ h i h e g b l _ e v g m x g n h j f Z p b x 9 ОЦЕНКА ПОДГОТОВКИ УЧАЩИХСЯ ШТАТА МИННЕСОТА K l j. A function may be thought of as a rule which takes each member x of a set and assigns, or maps it to the same value y known at its image x → Function → y A letter such as f, g or h is often used to stand for a functionThe Function which squares a number and adds on a 3, can be written as f(x) = x 2 5The same notion may also be used to show how a function affects particular values. A F O R M U L A F O R £ F k (x)y n "k A N D IT S G E N E R A L IZ A T IO N 1 T O rB O N A C C I P O L Y N O M IA L S M N S S W A M Y S ir G eorge W illiam s U niversity, M ontreal, P O , C anada 1 IN T R O D U C T IO N S om e years ago, C arlitz 1 had asked the readers to show that (D E F k2 n ~ k~ 1 = 2 nF n2 0 and n1 (2.

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H i b k Z g b _ d m j k Z RU PPHV 106 L j _ g b g i h w d k i e m Z l Z p b b b L H \ u k h d h \ h e v l g u o w e _ Z a h \ u o y q _ _ d D J M W 2 – 550 d. K j _ ^ k l \ Z d e b _ g l h \ g _ y \ e y x s b o k y d j _ ^ b l g u f b h j Z g b a Z p b y f b I j h q b _ h y a Z l _ e v k l \ Z. Sity function and the distribution function of X, respectively Note that F x (x) =P(X ≤x) and fx(x) =F(x) When X =ψ(Y), we want to obtain the probability density function of YLet f y(y) and F y(y) be the probability density function and the distribution function of Y, respectively Inthecaseofψ(X) >0,thedistributionfunctionofY, Fy(y), is rewritten as follows.

F h d k b p b e e b g j Z a j m r Z _ l k y i h ^ ^ _ c k l \ b _ f _ l Z e Z d l Z f Z a, \ u j Z Z l u \ Z _ f u o j _ a b k l _ g l g u f b Z d l _ j b y. ・j ・・・・・n ^ Y 04 N10 ・`12 ・箠/title> A t B G C g ・j. Y x0 y0 uniquely determines a solution In the case of second order equations, the basic theorem is this Theorem 121 Given x0 in the domain of the differentiable function g, and numbers y0 y0, there is a unique function f x which solves the differential equation (121) and satisfies the initial conditions f x0 y0 f x0 y0.

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