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< _ s ` a;. Nature voice e l c ` { c x e @ @ @ r y 𒆐s ɍ y ̃p ̎ 舵 y сa q o y. Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Michael B Sep 24, 14 The answer would be #f'(x) = 1/g(x)*g'(x)# or it can be written as #f'(x)=(g'(x))/g(x)# To solve this derivative you will need to follow the chain rule which states #F(x)=f(g(x))#.

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E x= ex > 0 ⇒ E(x) = e is concave up, increasing, and positive Proof Since E(x) = ex is the inverse of L(x) = lnx, then with y = ex, d dx ex = E0(x) = 1 L0(y) = 1 (lny)0 = 1 1 y = y = ex First, for m = 1, it is true Next, assume that it is true for k, then d k1 dxk1 ex = d dx d dxk ex = d dx (ex) = ex By the axiom of induction, it is. N X Y V N A H p e B A ̓񎟉 ȂǁA e p e B C x g 𕝍L Ă ܂ B l R O x ܂ł p ܂ B e ₨ ݕ A \ Z ȂǁA q l ̂ Ƀt L V u ɑΉ Ă ܂ ̂ŁA C y ɂ k B. ̂ڂ E t b O E o _ i ̓C x g L y 𐷂 グ ԕi ł B ʎY 鎖 Œቿ i ܂ I Ԃ̂ڂ e ቿ i ł p ӂ ܂ B.

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