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View caso informedocx from INGENIERIA CALCULO at Private University of the North A) La regla del trapecio 1 Identificamos f(x) y g(x) f(x) g(x) Donde el área será igual a 60 A=∫ ( f ( x )−g. Ú C b Ë Y ó ÷ À 3 r n b h 9 r f Æ f r ³ { Í Æ E ó b h Æ g Ô × b h Æ f p ß £ b h $ b h Æ E þ $ ý à g · ß × b h « r ø Æ f 9 r £ ´ 9 h $ 3 h Ã ß E þ i w h × ³ f À m á Æ Ì { r ³ g Ì ¯ E ³ Î Æ h g Â þ ¢ þ % b h r ß S h À b r à h g. Chú ý Nếu các bạn đăng kí thành viên mà không nhận được email kích hoạt thì hãy kiểm tra thùng thư rác (spam) Nếu không biết cách truy cập vào thùng thư rác thì các bạn chịu khó Google hoặc đăng câu hỏi vào mục Hướng dẫn Trợ giúp để thành viên khác có thể hỗ trợ.

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I need help I checked in back of the textbook for the answer to work backwards to find out how to solve this problem The first equation given is g(x) = f(x) The answer to that is (12,4) How did the textbook get this answer?. ¹ ( d ¦' 'ì ö =>Y Má2 K 2 Ç ( ¥«º'ö#©«¸Ò%Ê'2 d> ( "@b S46õ /¡ ö =0 1 i>Y Má2 K 2 Ç ( / ;. ç J U î ó ô æ Y Z C b ` ô µ b È ö / O , ¹ ú Â ¶ Y ú < Ý A å ¦ Ý ô ` ç p Ú L ¥ f ¶ M ì < ± Þ ô æ Y / O , ¹ ¢ ¶ b Ø × ô ' Ö ó í b M ö Ú ï1?.

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The_Story_of_Jesus_1938_PURUCKE ê´ ê´BOOKMOBI È ) 2!. ù ^ b j ¾ Æ Ü · I ¸ y ?. (12,2) (10,4) (12,4) (3,4) (12,16) (12, 4) 1 Dividing the function by 2 divides all the yvalues by 2 as well So to get the new point, we will take the yvalue (4) and divide it by 2 to get 2 Therefore, the new point is (12,2) 2 Subtracting 2 from the input of the function makes all of the xvalues increase by 2 (in order to compensate for the subtraction) We will need to add 2 to.

And please walk me through this with words and how you solved it And one last equation g(x) = f(x)2 Please tell me what am I supposed to do with each equation and. Get the free "Surface plot of f(x, y)" widget for your website, blog, Wordpress, Blogger, or iGoogle Find more Engineering widgets in WolframAlpha. Stack Exchange network consists of 176 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack Exchange.

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