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Taking logarithm on both sides, we get m*ln(x) n*ln(y) = (mn)*ln(xy) Now differentiate with respect to x, we get m/x (n/y)*(dy/dx) = (mn)/(xy)*(1dy/dx).

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J K B L ?. L “ K < B < G J B E K D B”, L h f 54, K \ II, > h b \ b i j _ j Z h l d Z g Z f b g. Dy/dx = y/x We have x^m y^n = (xy)^(mn) Take (natural) logarithms of both sides ln(x^m y^n) = ln((xy)^(mn)) Then using the properties of logarithms we can.

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