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Proof lnexy = xy = lnex lney = ln(ex ·ey) Since lnx is onetoone, then exy = ex ·ey 1 = e0 = ex(−x) = ex ·e−x ⇒ e−x = 1 ex ex−y = ex(−y) = ex ·e−y = ex · 1 ey ex ey • For r = m ∈ N, emx = e z }m { x···x = z }m { ex ···ex = (ex)m • For r = 1 n, n ∈ N and n 6= 0, ex = e n n x = e 1 nx n ⇒ e n x = (ex) 1 • For r rational, let r = m n, m, n ∈ N. C K ­ 1 2 A l g e b r a I I w i t h T r i g o n o m e t r y C o n c e p t s 1 C h a p t e r 1 0 – C o n i c S e c t i o n s A n s w e r K e y 8focus (0125, 0), directrix x = ­0125 ans­1001­02. P D F X C h a n g e V i e w e r w w w d o c u tr a c k c o m Click to buy NOW P from EEM 491 at Anadolu University.

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