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For h(w) = w 2 – 3, find h(2d 1) For every instance of the variable w, I'll need to plug in the expression 2d 1 I'll use parentheses to make the replacements clear for my next step h(2d 1) = (2d 1) 2 – 3 I need to multiply out the squared binomial next, and then simplify (2d 1) 2 – 3. The simplest case, apart from the trivial case of a constant function, is when y is a linear function of x, meaning that the graph of y is a line In this case, y = f(x) = mx b, for real numbers m and b, and the slope m is given by = =, where the symbol Δ is an abbreviation for "change in", and the combinations and refer to corresponding changes, ie. T C g ̓I W i s V c ̐ X ł B X c ₨ Ղ Ȃǂ̃C x g w グ 邽 ߂ɁA I W i ̃v g s V c p Ă݂܂ 񂩁H T V c ȊO ɂ p J g i A W p u L b v A ^ I ܂ł ܂ ܂ȑf ނ̃I W i v g ɑΉ Ă ܂ B P t Ă ܂ ̂ŁA b g ł 劽 } ł I I.

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Let w= f(x;y;z) be a function of three variables Introduce a new object, called thetotal di erential df= f xdx f ydy f zdz Formally behaves similarly to how fbehaves, fˇf x x f y y f z z However it is a new object (it is not the same as a small change in fas the book would claim), with its own rules of manipulation For us, the. Maxwell’s equations in integral form GG ∫Eda ⋅ =4πQ (Gauss's law Q is charge enclosed by surface S) S GG 1 ∂φB G ∫Eds ⋅ =−=emf (Faraday's law φB is B flux through surface bounded by C) C ct∂ s G ⋅ G = 4π I 1 ∂φE ∫ (Ampere's law I is current enclosed by contour C;. U _ b W E L o v ・・ J・ I @ X V ・} m I 6 ・ ・ ・Aﾔ ・Wｦ ・J ・I @0761 X V u 07 N f N C X E { C W v ・ J・ I @ X V 07 N5 ・@ E t F b g ・ Wｦ ・J ・I @0744 X V.

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